5/28/2019
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Program For Bisection Method In Fortran Language 9,3/10 5765 votes
I'm rusty with fortran and programming in general. I can't see my 'error' in a code that I wrote from scratch.
Basically I wanted to get some fun and solve for a temperature in thermodynamics where I must get 'T_f' which appear in a transcendental equation: ##Aln left ( frac{T_f^2}{T_1T_2} right )+2B[2T_f-(T_1T_2)]=0##.
Where T_1 is worth 100, T_2 is worth 200, A=2 and B=0.005.
Here is my code: that I compile along with The problem is that for the values I said above, I get the message 'There's an even number of root(s) in that interval'. Thus apparently the condition f(a)*f(b)>0 is satisfied. However when I enter the numbers in my pocket calculator I get f(a)=-2.3862.. and f(b)=2.3862.. where I truncated both values. Thus the condition is not satisfied.
I really don't see what's wrong. Any idea?
Edit: I tried with many different values for a and b. I even changed t_1 and t_2, same message.
Edit2: I've just tested the values of fa and fb. It thinks they are worth infinity. Going to check this out.
Edit3: No idea why it thinks they are worth infinity. o_0.
Edit4: ok it does not plug in t_1 and t_2 inside my function.
  1. History Of Fortran Programming Language
  2. Secant Method

History Of Fortran Programming Language

Fortran

Secant Method

Bisection method for the equation x3−2x−2 = 0 which has a single root between x=−4 and x = 2. Bisection method in fortran 90 Dec 14, 2012 #1. You should look at alternative methods of program flow control. It will really help you keep track of your code if you start making use of indentation. C++ Programming - Program for Bisection Method - Mathematical Algorithms - The method is also called the interval halving method, the binary search method.

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